{"id":563,"date":"2020-08-28T00:28:16","date_gmt":"2020-08-28T04:28:16","guid":{"rendered":"http:\/\/fiziko.net\/?page_id=563"},"modified":"2020-09-21T15:56:07","modified_gmt":"2020-09-21T19:56:07","slug":"simulacao-leis-de-newton","status":"publish","type":"page","link":"https:\/\/fiziko.net\/?page_id=563","title":{"rendered":"Simula\u00e7\u00e3o Leis de Newton"},"content":{"rendered":"\n<p class=\"has-text-align-left\">Um bloco de massa <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?m_{2}\"> est\u00e1 sobre um plano inclinado com um \u00e2ngulo de inclina\u00e7\u00e3o \u03b8 e est\u00e1 ligado por uma corda que passa sobre uma polia pequena a um segundo bloco suspenso de massa <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?m_{1}\">. <\/p>\n\n\n\n<p class=\"has-text-align-left\">H\u00e1 atrito entre o bloco <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?m_{2}\"> e o plano inclinado e os coeficientes de atrito cin\u00e9tico e est\u00e1tico s\u00e3o <img decoding=\"async\" title=\"\\mu _{c}\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\mu&amp;space;_{c}\"> e <img decoding=\"async\" title=\"\\mu _{e}\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\mu&amp;space;_{e}\">, respectivamente.<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter size-large is-resized\"><img fetchpriority=\"high\" decoding=\"async\" src=\"http:\/\/fiziko.net\/wp-content\/uploads\/2020\/08\/PlanoInclinado1.jpg\" alt=\"\" class=\"wp-image-569\" width=\"313\" height=\"408\" srcset=\"https:\/\/fiziko.net\/wp-content\/uploads\/2020\/08\/PlanoInclinado1.jpg 417w, https:\/\/fiziko.net\/wp-content\/uploads\/2020\/08\/PlanoInclinado1-230x300.jpg 230w\" sizes=\"(max-width: 313px) 100vw, 313px\" \/><\/figure><\/div>\n\n\n\n<p class=\"has-text-align-left\"><strong>Caso<\/strong> &#8211; Considere que o bloco de massa <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?m_{2}\"> est\u00e1 descendo o plano inclinado com acelera\u00e7\u00e3o igual a <\/p>\n\n\n\n<div class=\"wp-block-katex-display-block katex-eq\" data-katex-display=\"true\">a=g \\left[ \\frac{m_2(sen \\theta-\\mu_ccos \\theta)-m_1}{m_1+m_2} \\right]<\/div>\n\n\n\n<p class=\"has-text-align-left\">e subindo o plano inclinado com acelera\u00e7\u00e3o<\/p>\n\n\n\n<div class=\"wp-block-katex-display-block katex-eq\" data-katex-display=\"true\">a=-g \\left[ \\frac{m_2(sen \\theta+\\mu_ccos \\theta)-m_1}{m_1+m_2} \\right]<\/div>\n\n\n\n<p class=\"has-text-align-left\">Utilizando-se as defini\u00e7\u00f5es abaixo<\/p>\n\n\n\n<div class=\"wp-block-katex-display-block katex-eq\" data-katex-display=\"true\">\\begin{cases}\nm=\\frac{m_1}{m_2} \\\\\ncos^{2}\\theta=1-sen^{2}\\theta\n\\end{cases}<\/div>\n\n\n\n<p class=\"has-text-align-left\">mostre que a acelera\u00e7\u00e3o dos blocos \u00e9 nula e os blocos ficam na imin\u00eancia de se movimentarem, se os dois \u00e2ngulos para os quais os blocos ficam no limite de subir ou de descer o plano inclinado forem dados por<\/p>\n\n\n\n<div class=\"wp-block-katex-display-block katex-eq\" data-katex-display=\"true\">sen\\theta=\\frac{m \\pm \\mu_e\\sqrt{\\mu_{e}^{2}-m^{2}+1}}{\\mu_{e}^{2}+1}<\/div>\n\n\n\n<p class=\"has-text-align-left\">Para que as ra\u00edzes sejam sempre reais, tem-se que<\/p>\n\n\n\n<div class=\"wp-block-katex-display-block katex-eq\" data-katex-display=\"true\">m^{2} \\leqslant \\mu_{e}^{2}+1<\/div>\n\n\n\n<p class=\"has-text-align-left\">Ou seja, <\/p>\n\n\n\n<div class=\"wp-block-katex-display-block katex-eq\" data-katex-display=\"true\">\\begin{cases}\nm=0,6 \\\\\n\\mu_{e}=0,4\n\\end{cases}\n<\/div>\n\n\n\n<p class=\"has-text-align-left\">tem-se que<\/p>\n\n\n\n<div class=\"wp-block-katex-display-block katex-eq\" data-katex-display=\"true\">\n\\begin{cases}\n\\theta_{1}=12,05\u00b0 \\\\\n\\theta_{2}=55,66\u00b0\n\\end{cases}<\/div>\n\n\n\n<p class=\"has-text-align-left\">Crie uma aplica\u00e7\u00e3o, no <strong><em>Geogebra<\/em><\/strong> ou no <strong><em>AppInventor<\/em><\/strong>, que mostre esse comportamento.<\/p>\n\n\n\n<p class=\"has-text-align-left\">(a)  Solicite que o usu\u00e1rio forne\u00e7a os valores das massas <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?m_{1}\"> e <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?m_{2}\">;<\/p>\n\n\n\n<p class=\"has-text-align-left\">(b) Solicite que o usu\u00e1rio forne\u00e7a os valores dos coeficientes de atrito  cin\u00e9tico  <img decoding=\"async\" title=\"\\mu _{c}\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\mu&amp;space;_{c}\"> e coeficiente de atrito est\u00e1tico <img decoding=\"async\" title=\"\\mu _{e}\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\mu&amp;space;_{e}\">;<\/p>\n\n\n\n<p class=\"has-text-align-left\">(c) O programa deve informar ao usu\u00e1rio os valores dos dois \u00e2ngulos limites <img decoding=\"async\" title=\"\\theta_{1}\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\theta_{1}\"> e <img decoding=\"async\" title=\"\\theta_{2}\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\theta_{2}\">, para os quais os blocos permanecer\u00e3o em repouso;<\/p>\n\n\n\n<p class=\"has-text-align-left\">(d) O programa deve informar para o usu\u00e1rio a acelera\u00e7\u00e3o dos blocos nas condi\u00e7\u00f5es tratadas acima;<\/p>\n\n\n\n<p>(e) O programa deve informar quando as ra\u00edzes n\u00e3o forem reais.<\/p>\n\n\n\n<p class=\"has-text-align-left\">Bom trabalho!<\/p>\n\n\n\n<figure class=\"wp-block-embed-youtube aligncenter wp-block-embed is-type-video is-provider-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<div class='embed-container'><iframe title=\"Simula\u00e7\u00e3o sobre For\u00e7a de Atrito e Plano Inclinado\" width=\"1920\" height=\"1080\" src=\"https:\/\/www.youtube.com\/embed\/60MxawSCz-Y?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture\" allowfullscreen><\/iframe><\/div>\n<\/div><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Um bloco de massa est\u00e1 sobre um plano inclinado com um \u00e2ngulo de inclina\u00e7\u00e3o \u03b8 e est\u00e1 ligado por uma corda que passa sobre uma polia pequena a um segundo bloco suspenso de massa . H\u00e1 atrito entre o bloco e o plano inclinado e os coeficientes de atrito cin\u00e9tico e est\u00e1tico s\u00e3o e ,&hellip; <br \/> <a class=\"read-more\" href=\"https:\/\/fiziko.net\/?page_id=563\">Leia mais<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"footnotes":""},"class_list":["post-563","page","type-page","status-publish","hentry"],"_links":{"self":[{"href":"https:\/\/fiziko.net\/index.php?rest_route=\/wp\/v2\/pages\/563","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/fiziko.net\/index.php?rest_route=\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/fiziko.net\/index.php?rest_route=\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/fiziko.net\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/fiziko.net\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=563"}],"version-history":[{"count":8,"href":"https:\/\/fiziko.net\/index.php?rest_route=\/wp\/v2\/pages\/563\/revisions"}],"predecessor-version":[{"id":591,"href":"https:\/\/fiziko.net\/index.php?rest_route=\/wp\/v2\/pages\/563\/revisions\/591"}],"wp:attachment":[{"href":"https:\/\/fiziko.net\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=563"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}